20=40-4f-2(3f-2)

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Solution for 20=40-4f-2(3f-2) equation: 



20=40-4f-2(3f-2)

We move all terms to the left:

20-(40-4f-2(3f-2))=0



We calculate terms in parentheses: -(40-4f-2(3f-2)), so:

40-4f-2(3f-2)

determiningTheFunctionDomain
-4f-2(3f-2)+40

We multiply parentheses

-4f-6f+4+40

We add all the numbers together, and all the variables

-10f+44

Back to the equation:

-(-10f+44)



We get rid of parentheses

10f-44+20=0

We add all the numbers together, and all the variables

10f-24=0

We move all terms containing f to the left, all other terms to the right

10f=24

f=24/10

f=2+2/5

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