4n+2=6(31n-32)

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Solution for 4n+2=6(31n-32) equation: 



4n+2=6(31n-32)

We move all terms to the left:

4n+2-(6(31n-32))=0



We calculate terms in parentheses: -(6(31n-32)), so:

6(31n-32)

We multiply parentheses

186n-192

Back to the equation:

-(186n-192)



We get rid of parentheses

4n-186n+192+2=0

We add all the numbers together, and all the variables

-182n+194=0

We move all terms containing n to the left, all other terms to the right

-182n=-194

n=-194/-182

n=1+6/91

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