4n(4n+8)=0

Solution for 4n(4n+8)=0 equation:

4n(4n+8)=0

We multiply parentheses

16n^2+32n=0

a = 16; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·16·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*16}=\frac{-64}{32}
=-2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*16}=\frac{0}{32}
=0
$