11(z-3)=7(z+3)

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Solution for 11(z-3)=7(z+3) equation: 



11(z-3)=7(z+3)

We move all terms to the left:

11(z-3)-(7(z+3))=0

We multiply parentheses

11z-(7(z+3))-33=0



We calculate terms in parentheses: -(7(z+3)), so:

7(z+3)

We multiply parentheses

7z+21

Back to the equation:

-(7z+21)



We get rid of parentheses

11z-7z-21-33=0

We add all the numbers together, and all the variables

4z-54=0

We move all terms containing z to the left, all other terms to the right

4z=54

z=54/4

z=13+1/2

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