4m2+3m=4

Solution for 4m2+3m=4 equation:

4m^2+3m=4

We move all terms to the left:

4m^2+3m-(4)=0

a = 4; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·4·(-4)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{73}}{2*4}=\frac{-3-\sqrt{73}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{73}}{2*4}=\frac{-3+\sqrt{73}}{8}
$