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x2+3.25x+x=0
We add all the numbers together, and all the variables
x^2+4.25x=0
a = 1; b = 4.25; c = 0;
Δ = b2-4ac
Δ = 4.252-4·1·0
Δ = 18.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.25)-\sqrt{18.0625}}{2*1}=\frac{-4.25-\sqrt{18.0625}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.25)+\sqrt{18.0625}}{2*1}=\frac{-4.25+\sqrt{18.0625}}{2} $
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