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4m^2+34m+30=0
a = 4; b = 34; c = +30;
Δ = b2-4ac
Δ = 342-4·4·30
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-26}{2*4}=\frac{-60}{8} =-7+1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+26}{2*4}=\frac{-8}{8} =-1 $
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