-3X2+9=9-6x

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Solution for -3X2+9=9-6x equation:



-3X^2+9=9-6X
We move all terms to the left:
-3X^2+9-(9-6X)=0
We add all the numbers together, and all the variables
-3X^2-(-6X+9)+9=0
We get rid of parentheses
-3X^2+6X-9+9=0
We add all the numbers together, and all the variables
-3X^2+6X=0
a = -3; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-3)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-3}=\frac{-12}{-6} =+2 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-3}=\frac{0}{-6} =0 $

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