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2(x+4)=7(x-3/5)
We move all terms to the left:
2(x+4)-(7(x-3/5))=0
We add all the numbers together, and all the variables
2(x+4)-(7(+x-3/5))=0
We multiply parentheses
2x-(7(+x-3/5))+8=0
We multiply all the terms by the denominator
2x*5))-(7(+x-3+8*5))=0
We add all the numbers together, and all the variables
2x*5))-(7(x+37))=0
We add all the numbers together, and all the variables
2x*5))-(7(x=0
Wy multiply elements
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{20}=0$
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