4m+40=-5(1-3m)+4m

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Solution for 4m+40=-5(1-3m)+4m equation: 



4m+40=-5(1-3m)+4m

We move all terms to the left:

4m+40-(-5(1-3m)+4m)=0

We add all the numbers together, and all the variables

4m-(-5(-3m+1)+4m)+40=0



We calculate terms in parentheses: -(-5(-3m+1)+4m), so:

-5(-3m+1)+4m

We add all the numbers together, and all the variables

4m-5(-3m+1)

We multiply parentheses

4m+15m-5

We add all the numbers together, and all the variables

19m-5

Back to the equation:

-(19m-5)



We get rid of parentheses

4m-19m+5+40=0

We add all the numbers together, and all the variables

-15m+45=0

We move all terms containing m to the left, all other terms to the right

-15m=-45

m=-45/-15

m=+3

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