4c-2(c+2)=1-(2c-5)

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Solution for 4c-2(c+2)=1-(2c-5) equation: 



4c-2(c+2)=1-(2c-5)

We move all terms to the left:

4c-2(c+2)-(1-(2c-5))=0

We multiply parentheses

4c-2c-(1-(2c-5))-4=0



We calculate terms in parentheses: -(1-(2c-5)), so:

1-(2c-5)

determiningTheFunctionDomain
-(2c-5)+1

We get rid of parentheses

-2c+5+1

We add all the numbers together, and all the variables

-2c+6

Back to the equation:

-(-2c+6)



We add all the numbers together, and all the variables

2c-(-2c+6)-4=0

We get rid of parentheses

2c+2c-6-4=0

We add all the numbers together, and all the variables

4c-10=0

We move all terms containing c to the left, all other terms to the right

4c=10

c=10/4

c=2+1/2

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