4j+3=12j+35

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Solution for 4j+3=12j+35 equation: 



4j+3=12j+35

We move all terms to the left:

4j+3-(12j+35)=0

We get rid of parentheses

4j-12j-35+3=0

We add all the numbers together, and all the variables

-8j-32=0

We move all terms containing j to the left, all other terms to the right

-8j=32

j=32/-8

j=-4

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