5x2/3x=12

Solution for 5x2/3x=12 equation:

5x^2/3x=12

We move all terms to the left:

5x^2/3x-(12)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We multiply all the terms by the denominator


5x^2-12*3x=0

Wy multiply elements

5x^2-36x=0

a = 5; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·5·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*5}=\frac{72}{10}
=7+1/5
$