4f+4(2f-5)=28

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Solution for 4f+4(2f-5)=28 equation: 



4f+4(2f-5)=28

We move all terms to the left:

4f+4(2f-5)-(28)=0

We multiply parentheses

4f+8f-20-28=0

We add all the numbers together, and all the variables

12f-48=0

We move all terms containing f to the left, all other terms to the right

12f=48

f=48/12

f=4

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