4f+1=2(2f+3)-5

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Solution for 4f+1=2(2f+3)-5 equation:



4f+1=2(2f+3)-5
We move all terms to the left:
4f+1-(2(2f+3)-5)=0
We calculate terms in parentheses: -(2(2f+3)-5), so:
2(2f+3)-5
We multiply parentheses
4f+6-5
We add all the numbers together, and all the variables
4f+1
Back to the equation:
-(4f+1)
We get rid of parentheses
4f-4f-1+1=0
We add all the numbers together, and all the variables
=0
f=0/1
f=0

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