a2+a2+a2=3a2

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Solution for a2+a2+a2=3a2 equation: 



a2+a2+a2=3a^2

We move all terms to the left:

a2+a2+a2-(3a^2)=0

determiningTheFunctionDomain
-3a^2+a2+a2+a2=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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