4c+5=3(2c-1)

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Solution for 4c+5=3(2c-1) equation: 



4c+5=3(2c-1)

We move all terms to the left:

4c+5-(3(2c-1))=0



We calculate terms in parentheses: -(3(2c-1)), so:

3(2c-1)

We multiply parentheses

6c-3

Back to the equation:

-(6c-3)



We get rid of parentheses

4c-6c+3+5=0

We add all the numbers together, and all the variables

-2c+8=0

We move all terms containing c to the left, all other terms to the right

-2c=-8

c=-8/-2

c=+4

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