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4c+3=3(c+4)
We move all terms to the left:
4c+3-(3(c+4))=0
We calculate terms in parentheses: -(3(c+4)), so:We get rid of parentheses
3(c+4)
We multiply parentheses
3c+12
Back to the equation:
-(3c+12)
4c-3c-12+3=0
We add all the numbers together, and all the variables
c-9=0
We move all terms containing c to the left, all other terms to the right
c=9
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