12(b+2)=8(b+4)

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Solution for 12(b+2)=8(b+4) equation: 



12(b+2)=8(b+4)

We move all terms to the left:

12(b+2)-(8(b+4))=0

We multiply parentheses

12b-(8(b+4))+24=0



We calculate terms in parentheses: -(8(b+4)), so:

8(b+4)

We multiply parentheses

8b+32

Back to the equation:

-(8b+32)



We get rid of parentheses

12b-8b-32+24=0

We add all the numbers together, and all the variables

4b-8=0

We move all terms containing b to the left, all other terms to the right

4b=8

b=8/4

b=2

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