4b-2(b-7)=3+3b

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Solution for 4b-2(b-7)=3+3b equation: 



4b-2(b-7)=3+3b

We move all terms to the left:

4b-2(b-7)-(3+3b)=0

We add all the numbers together, and all the variables

4b-2(b-7)-(3b+3)=0

We multiply parentheses

4b-2b-(3b+3)+14=0

We get rid of parentheses

4b-2b-3b-3+14=0

We add all the numbers together, and all the variables

-1b+11=0

We move all terms containing b to the left, all other terms to the right

-b=-11

b=-11/-1

b=+11

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