3(c-1)+2(3c+1)=-(3c=1)

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Solution for 3(c-1)+2(3c+1)=-(3c=1) equation: 



3(c-1)+2(3c+1)=-(3c=1)

We move all terms to the left:

3(c-1)+2(3c+1)-(-(3c)=0

We multiply parentheses

3c+6c-(-3c-3+2=0

We add all the numbers together, and all the variables

9c-(-3c-3+2=0

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