4b+3b-68=1+7

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Solution for 4b+3b-68=1+7 equation: 



4b+3b-68=1+7

We move all terms to the left:

4b+3b-68-(1+7)=0

We add all the numbers together, and all the variables

4b+3b-68-8=0

We add all the numbers together, and all the variables

7b-76=0

We move all terms containing b to the left, all other terms to the right

7b=76

b=76/7

b=10+6/7

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