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8-3x=x-4(2+2x)
We move all terms to the left:
8-3x-(x-4(2+2x))=0
We add all the numbers together, and all the variables
-3x-(x-4(2x+2))+8=0
We calculate terms in parentheses: -(x-4(2x+2)), so:We get rid of parentheses
x-4(2x+2)
We multiply parentheses
x-8x-8
We add all the numbers together, and all the variables
-7x-8
Back to the equation:
-(-7x-8)
-3x+7x+8+8=0
We add all the numbers together, and all the variables
4x+16=0
We move all terms containing x to the left, all other terms to the right
4x=-16
x=-16/4
x=-4
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