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4a=2-(a-4)
We move all terms to the left:
4a-(2-(a-4))=0
We calculate terms in parentheses: -(2-(a-4)), so:We get rid of parentheses
2-(a-4)
determiningTheFunctionDomain -(a-4)+2
We get rid of parentheses
-a+4+2
We add all the numbers together, and all the variables
-1a+6
Back to the equation:
-(-1a+6)
4a+1a-6=0
We add all the numbers together, and all the variables
5a-6=0
We move all terms containing a to the left, all other terms to the right
5a=6
a=6/5
a=1+1/5
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