4a-48+3a-19=4a

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Solution for 4a-48+3a-19=4a equation: 



4a-48+3a-19=4a

We move all terms to the left:

4a-48+3a-19-(4a)=0

We add all the numbers together, and all the variables

3a-67=0

We move all terms containing a to the left, all other terms to the right

3a=67

a=67/3

a=22+1/3

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