7(-3y+2)=8(3y2)

Solution for 7(-3y+2)=8(3y2) equation:

7(-3y+2)=8(3y^2)

We move all terms to the left:

7(-3y+2)-(8(3y^2))=0

determiningTheFunctionDomain
7(-3y+2)-83y^2=0

We add all the numbers together, and all the variables

-83y^2+7(-3y+2)=0

We multiply parentheses

-83y^2-21y+14=0

a = -83; b = -21; c = +14;
Δ = b2-4ac
Δ = -212-4·(-83)·14
Δ = 5089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{5089}}{2*-83}=\frac{21-\sqrt{5089}}{-166}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{5089}}{2*-83}=\frac{21+\sqrt{5089}}{-166}
$