4a+3(a+2)=8a-(6+a)

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Solution for 4a+3(a+2)=8a-(6+a) equation: 



4a+3(a+2)=8a-(6+a)

We move all terms to the left:

4a+3(a+2)-(8a-(6+a))=0

We add all the numbers together, and all the variables

4a+3(a+2)-(8a-(a+6))=0

We multiply parentheses

4a+3a-(8a-(a+6))+6=0



We calculate terms in parentheses: -(8a-(a+6)), so:

8a-(a+6)

We get rid of parentheses

8a-a-6

We add all the numbers together, and all the variables

7a-6

Back to the equation:

-(7a-6)



We add all the numbers together, and all the variables

7a-(7a-6)+6=0

We get rid of parentheses

7a-7a+6+6=0

We add all the numbers together, and all the variables

12!=0

There is no solution for this equation

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