(2x+1)+(3x+2)=(6x-4)

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Solution for (2x+1)+(3x+2)=(6x-4) equation: 



(2x+1)+(3x+2)=(6x-4)

We move all terms to the left:

(2x+1)+(3x+2)-((6x-4))=0

We get rid of parentheses

2x+3x-((6x-4))+1+2=0



We calculate terms in parentheses: -((6x-4)), so:

(6x-4)

We get rid of parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

5x-(6x-4)+3=0

We get rid of parentheses

5x-6x+4+3=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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