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4=2/3(x-12
We move all terms to the left:
4-(2/3(x-12)=0
Domain of the equation: 3(x-12)+4!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3(x-12)!=-4
x∈R
-(2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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