-3(x-2)+23=7(x+3)-12

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Solution for -3(x-2)+23=7(x+3)-12 equation: 



-3(x-2)+23=7(x+3)-12

We move all terms to the left:

-3(x-2)+23-(7(x+3)-12)=0

We multiply parentheses

-3x-(7(x+3)-12)+6+23=0



We calculate terms in parentheses: -(7(x+3)-12), so:

7(x+3)-12

We multiply parentheses

7x+21-12

We add all the numbers together, and all the variables

7x+9

Back to the equation:

-(7x+9)



We add all the numbers together, and all the variables

-3x-(7x+9)+29=0

We get rid of parentheses

-3x-7x-9+29=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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