3(2v+4)=5(v+1)+3

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Solution for 3(2v+4)=5(v+1)+3 equation: 



3(2v+4)=5(v+1)+3

We move all terms to the left:

3(2v+4)-(5(v+1)+3)=0

We multiply parentheses

6v-(5(v+1)+3)+12=0



We calculate terms in parentheses: -(5(v+1)+3), so:

5(v+1)+3

We multiply parentheses

5v+5+3

We add all the numbers together, and all the variables

5v+8

Back to the equation:

-(5v+8)



We get rid of parentheses

6v-5v-8+12=0

We add all the numbers together, and all the variables

v+4=0

We move all terms containing v to the left, all other terms to the right

v=-4

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