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4=2/3(1x-12)
We move all terms to the left:
4-(2/3(1x-12))=0
Domain of the equation: 3(1x-12))!=0We add all the numbers together, and all the variables
x∈R
-(2/3(x-12))+4=0
We multiply all the terms by the denominator
-(2+4*3(x-12))=0
We calculate terms in parentheses: -(2+4*3(x-12)), so:
2+4*3(x-12)
determiningTheFunctionDomain 4*3(x-12)+2
Wy multiply elements
12x(x+2
Back to the equation:
-(12x(x+2)
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
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12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
We calculate terms in parentheses: -(12x(x+2), so:
12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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12x(x+2
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