4(x+2)-7(x-2)=x-6

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Solution for 4(x+2)-7(x-2)=x-6 equation:



4(x+2)-7(x-2)=x-6
We move all terms to the left:
4(x+2)-7(x-2)-(x-6)=0
We multiply parentheses
4x-7x-(x-6)+8+14=0
We get rid of parentheses
4x-7x-x+6+8+14=0
We add all the numbers together, and all the variables
-4x+28=0
We move all terms containing x to the left, all other terms to the right
-4x=-28
x=-28/-4
x=+7

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