4=2+(2/5)*t

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Solution for 4=2+(2/5)*t equation: 



4=2+(2/5)*t

We move all terms to the left:

4-(2+(2/5)*t)=0



Domain of the equation: 5)*t)!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

-(2+(+2/5)*t)+4=0

We multiply all the terms by the denominator


-(2+(+2+4*5)*t)=0



We calculate terms in parentheses: -(2+(+2+4*5)*t), so:

2+(+2+4*5)*t

determiningTheFunctionDomain
(+2+4*5)*t+2

We add all the numbers together, and all the variables

22*t+2

We add all the numbers together, and all the variables

22t+2

Back to the equation:

-(22t+2)



We get rid of parentheses

-22t-2=0

We move all terms containing t to the left, all other terms to the right

-22t=2

t=2/-22

t=-1/11

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