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6(2x-3)=3(4x-5)
We move all terms to the left:
6(2x-3)-(3(4x-5))=0
We multiply parentheses
12x-(3(4x-5))-18=0
We calculate terms in parentheses: -(3(4x-5)), so:We get rid of parentheses
3(4x-5)
We multiply parentheses
12x-15
Back to the equation:
-(12x-15)
12x-12x+15-18=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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