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4=1/8(3x+16
We move all terms to the left:
4-(1/8(3x+16)=0
Domain of the equation: 8(3x+16)+4!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
8(3x+16)!=-4
x∈R
-(1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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