4=(2t+1)/5

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Solution for 4=(2t+1)/5 equation:



4=(2t+1)/5
We move all terms to the left:
4-((2t+1)/5)=0
We multiply all the terms by the denominator
-((2t+1)+4*5)=0
We calculate terms in parentheses: -((2t+1)+4*5), so:
(2t+1)+4*5
We add all the numbers together, and all the variables
(2t+1)+20
We get rid of parentheses
2t+1+20
We add all the numbers together, and all the variables
2t+21
Back to the equation:
-(2t+21)
We get rid of parentheses
-2t-21=0
We move all terms containing t to the left, all other terms to the right
-2t=21
t=21/-2
t=-10+1/2

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