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q/3+(1-5)/3=8
We move all terms to the left:
q/3+(1-5)/3-(8)=0
determiningTheFunctionDomain q/3-8+(1-5)/3=0
We add all the numbers together, and all the variables
q/3-8+(-4)/3=0
We multiply all the terms by the denominator
q-8*3+(-4)=0
We add all the numbers together, and all the variables
q-28=0
We move all terms containing q to the left, all other terms to the right
q=28
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