49=4+3(4k-1)

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Solution for 49=4+3(4k-1) equation: 



49=4+3(4k-1)

We move all terms to the left:

49-(4+3(4k-1))=0



We calculate terms in parentheses: -(4+3(4k-1)), so:

4+3(4k-1)

determiningTheFunctionDomain
3(4k-1)+4

We multiply parentheses

12k-3+4

We add all the numbers together, and all the variables

12k+1

Back to the equation:

-(12k+1)



We get rid of parentheses

-12k-1+49=0

We add all the numbers together, and all the variables

-12k+48=0

We move all terms containing k to the left, all other terms to the right

-12k=-48

k=-48/-12

k=+4

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