-33=3(1+3a)+3a

Solution for -33=3(1+3a)+3a equation:

-33=3(1+3a)+3a

We move all terms to the left:

-33-(3(1+3a)+3a)=0

We add all the numbers together, and all the variables

-(3(3a+1)+3a)-33=0


We calculate terms in parentheses: -(3(3a+1)+3a), so:

3(3a+1)+3a

We add all the numbers together, and all the variables

3a+3(3a+1)

We multiply parentheses

3a+9a+3

We add all the numbers together, and all the variables

12a+3

Back to the equation:

-(12a+3)


We get rid of parentheses

-12a-3-33=0

We add all the numbers together, and all the variables

-12a-36=0

We move all terms containing a to the left, all other terms to the right

-12a=36

a=36/-12

a=-3