490t2-250=0

Solution for 490t2-250=0 equation:

490t^2-250=0

a = 490; b = 0; c = -250;
Δ = b2-4ac
Δ = 02-4·490·(-250)
Δ = 490000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{490000}=700$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-700}{2*490}=\frac{-700}{980}
=-5/7
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+700}{2*490}=\frac{700}{980}
=5/7
$