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8-10v^2=-352
We move all terms to the left:
8-10v^2-(-352)=0
We add all the numbers together, and all the variables
-10v^2+360=0
a = -10; b = 0; c = +360;
Δ = b2-4ac
Δ = 02-4·(-10)·360
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-10}=\frac{-120}{-20} =+6 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-10}=\frac{120}{-20} =-6 $
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