49-(2c+)=4(c+6)+c

Solution for 49-(2c+)=4(c+6)+c equation:

49-(2c+)=4(c+6)+c

We move all terms to the left:

49-(2c+)-(4(c+6)+c)=0

We add all the numbers together, and all the variables

-(+2c)-(4(c+6)+c)+49=0

We get rid of parentheses

-2c-(4(c+6)+c)+49=0


We calculate terms in parentheses: -(4(c+6)+c), so:

4(c+6)+c

We add all the numbers together, and all the variables

c+4(c+6)

We multiply parentheses

c+4c+24

We add all the numbers together, and all the variables

5c+24

Back to the equation:

-(5c+24)


We get rid of parentheses

-2c-5c-24+49=0

We add all the numbers together, and all the variables

-7c+25=0

We move all terms containing c to the left, all other terms to the right

-7c=-25

c=-25/-7

c=3+4/7