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2(6x+9)=3(3x-4)*
We move all terms to the left:
2(6x+9)-(3(3x-4)*)=0
We multiply parentheses
12x-(3(3x-4)*)+18=0
We calculate terms in parentheses: -(3(3x-4)*), so:We get rid of parentheses
3(3x-4)*
We multiply parentheses
9x-12
Back to the equation:
-(9x-12)
12x-9x+12+18=0
We add all the numbers together, and all the variables
3x+30=0
We move all terms containing x to the left, all other terms to the right
3x=-30
x=-30/3
x=-10
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