49+14x+X2=228

Solution for 49+14x+X2=228 equation:

49+14x+x2=228

We move all terms to the left:

49+14x+x2-(228)=0

We add all the numbers together, and all the variables

x^2+14x-179=0

a = 1; b = 14; c = -179;
Δ = b2-4ac
Δ = 142-4·1·(-179)
Δ = 912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{912}=\sqrt{16*57}=\sqrt{16}*\sqrt{57}=4\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4\sqrt{57}}{2*1}=\frac{-14-4\sqrt{57}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4\sqrt{57}}{2*1}=\frac{-14+4\sqrt{57}}{2}
$