3(2y-1)-5(3y+2)+2(5y-3)=(-18)

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Solution for 3(2y-1)-5(3y+2)+2(5y-3)=(-18) equation: 



3(2y-1)-5(3y+2)+2(5y-3)=(-18)

We move all terms to the left:

3(2y-1)-5(3y+2)+2(5y-3)-((-18))=0

We add all the numbers together, and all the variables

3(2y-1)-5(3y+2)+2(5y-3)+18=0

We multiply parentheses

6y-15y+10y-3-10-6+18=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1

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