48=5(3y+3)-3(2y-2)

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Solution for 48=5(3y+3)-3(2y-2) equation: 



48=5(3y+3)-3(2y-2)

We move all terms to the left:

48-(5(3y+3)-3(2y-2))=0



We calculate terms in parentheses: -(5(3y+3)-3(2y-2)), so:

5(3y+3)-3(2y-2)

We multiply parentheses

15y-6y+15+6

We add all the numbers together, and all the variables

9y+21

Back to the equation:

-(9y+21)



We get rid of parentheses

-9y-21+48=0

We add all the numbers together, and all the variables

-9y+27=0

We move all terms containing y to the left, all other terms to the right

-9y=-27

y=-27/-9

y=+3

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