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7x^2+70x+112=0
a = 7; b = 70; c = +112;
Δ = b2-4ac
Δ = 702-4·7·112
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-42}{2*7}=\frac{-112}{14} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+42}{2*7}=\frac{-28}{14} =-2 $
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