48=4c-4(5-4c)

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Solution for 48=4c-4(5-4c) equation: 



48=4c-4(5-4c)

We move all terms to the left:

48-(4c-4(5-4c))=0

We add all the numbers together, and all the variables

-(4c-4(-4c+5))+48=0



We calculate terms in parentheses: -(4c-4(-4c+5)), so:

4c-4(-4c+5)

We multiply parentheses

4c+16c-20

We add all the numbers together, and all the variables

20c-20

Back to the equation:

-(20c-20)



We get rid of parentheses

-20c+20+48=0

We add all the numbers together, and all the variables

-20c+68=0

We move all terms containing c to the left, all other terms to the right

-20c=-68

c=-68/-20

c=3+2/5

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