2y-3(y+1)=-(5y+3)

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Solution for 2y-3(y+1)=-(5y+3) equation: 



2y-3(y+1)=-(5y+3)

We move all terms to the left:

2y-3(y+1)-(-(5y+3))=0

We multiply parentheses

2y-3y-(-(5y+3))-3=0



We calculate terms in parentheses: -(-(5y+3)), so:

-(5y+3)

We get rid of parentheses

-5y-3

Back to the equation:

-(-5y-3)



We add all the numbers together, and all the variables

-1y-(-5y-3)-3=0

We get rid of parentheses

-1y+5y+3-3=0

We add all the numbers together, and all the variables

4y=0

y=0/4

y=0

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